Question

Find the smallest number which on adding 19 to it is exactly divisible by 28, 36 and 45.

• A. 1200
• B. 1214
• C. 1241
• D. 1251

Answer 1

The correct option is C 1241

First we have to find L.C.M. of 28, 36 and 45.

$\therefore$ L.C.M. of 28, 36 and 45 = 2 × 2 × 3 × 3 × 5 × 7 = 1260

$\therefore$ the required number is 1260 - 19 = 1241

Hence, if we add 19 to 1241 we will get 1260 which is exactly divisible by 28, 36 and 45.