Find the smallest number which on being added 23 to it, is exactly divisible by 32,36,48,96.
Step 1: Find L.C.M. of 32,36,48,96:
32=2×2×2×2×236=2×2×3×348=2×2×2×2×396=2×2×2×2×2×3
LCM=2×2×2×2×2×3×3=288
Step 2: Now, subtract 23 from it:288-23=265Hence, 265 is the required smallest number.