Find the smallest number which should be multiplied to 231525 to make it a perfect cube.
Prime factorising 231525, we get,
231525=3×3×3×5×5×7×7×7
=33×52×73.
We know that a perfect cube number has its factor with an exponent as multiples of 3.
Here, exponent of 3's is 3, exponent of 5's is 2 and exponent of 7's is 3.
So we need to multiply another 5 to the factorization to make 2,31,525 a perfect cube.
Hence, the smallest number by which 2,31,525 must be multiplied to obtain a perfect cube is 5.
Hence, option A is correct.