Find the smallest number which, when divided by 12,15,18,24 and 36 leaves no remainder.
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Solution
Step: Find the smallest number
The smallest number which is exactly divisible by each given number is their L.C.M. (0.5 mark) ∴ The smallest number is L.C.M. of 12,15,18,24 and 36.
(1 mark) ∴L.C.M.=2×2×2×3×3×5=360 (1 mark)
Hence, the smallest number is 360. (0.5 mark)