Question

Find the smallest number which, when divided by $12,15,18,24$ and $36$ leaves no remainder.

Answer 1

Step: Find the smallest number

The smallest number which is exactly divisible by each given number is their $L.C.M.$ (0.5 mark)
$\therefore$ The smallest number is $L.C.M.$ of $12,15,18,24$ and $36$.
(1 mark)
$\therefore L.C.M.=2\times 2\times 2\times 3\times 3\times 5=360$ (1 mark)
Hence, the smallest number is $360$. (0.5 mark)