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Question
Find the smallest number which when divided by 23, 45, 5, 27 and 48 leaves a remainder 7.
Find the smallest number which when divided by 23, 45, 5, 27 and 48 leaves a remainder 7.
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Solution
The correct option is A 49687
The LCM of the given numbers is 49680 which means when this number divided by the given numbers will give a remainder zero. So in order to get number which leaves a remainder of 7 when divided by 23, 45, 5, 27, 48 we have to add 7 to 49680. The number which is required is 49687.
49687
The LCM of the given numbers is 49680 which means when this number divided by the given numbers will give a remainder zero. So in order to get number which leaves a remainder of 7 when divided by 23, 45, 5, 27, 48 we have to add 7 to 49680. The number which is required is 49687.
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