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Question

Find the smallest number which, when increased by one is exactly divisible by 12,18,24,32 and 40.

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Solution

Step: Find the smallest number

L.C.M. of given numbers

L.C.M.=2×2×2×2×2×3×3×5=1440
The smallest number =14401
=1439
Hence, the smallest number is 1439.

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