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Question

Find the smallest positive integer such that it has exactly 100 different positive divisors including 1 and the number itself.

A
45360
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B
45370
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C
45380
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D
45390
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Solution

The correct option is A 45360
We know That total No. of factors
=product of (prime nos power+1)

If N is the number of different divisors:

N=(p1+1)(p2+1)(pn+1)

100=22×52

=2×2×5×5=(1+1)(1+1)(4+1)(4+1)

Then the integer n= ap11ap22apnn

For the smallest value: p1=4,p2=4,p3=1,p4=1

Then,
n=a41×a42×a13×a14

=24345171

=168157

=45360

Hence, the smallest number is 45360.

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