Question

Find the smallest positive integer which when divided by 3 ,7, 11 leaves remainder 1, 6, 5 respectively

Answer 1

There is some mistake in the question .
the procedure to solve this kind of questions is given below. Check ur question and find the solution

When a number is divided by 7,9 and 11 it leaves 1,2 and 3 as remainders respectively

Subtract the remainder from the divisor, then

7-1=6
9-2=7
11-3=8
Repeat the above process until you get the same number
6-1=5=n
7-2=5 =n
8-3=5=n
When equal then

Smallest no=( Lcm -n)÷2

Lcm is the Lcm of the divisor

So Lcm of (7,9,11)=693
Number=(693-5)÷2

=688÷2

=344