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Question

Find the smallest square number that is divisible by each of the numbers 8,15and20.

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Solution

Let us find LCM of 8,15 and 20
8=2×2×2
15=3×5
20=2×2×5
So, LCM =2×2×2×3×5=120.
For nos which are not in pairs in LCM factors, we need to multiply 120 by 2, 3 and 5 to make it a perfect square.
Required Number =120×2×3×5=3600

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