1
Question
Find the solution for the equation 4y=20 by trial and error method.
Find the solution for the equation 4y=20 by trial and error method.
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Solution
The correct option is D 5
Given equation is 4y=20
Substituting value (y)
Value of LHS (4y)
Value of RHS (20)
Whether LHS and RHS are equal
1
= 4×1
= 4
20
No
2
=4×2
= 8
20
No
3
=4×3
= 12
20
No
4
=4×4
= 16
20
No
5
=4×5
= 20
20
Yes
As LHS=RHS for y = 5,
Hence y = 5 is the solution of the given equation.
Given equation is 4y=20
| Substituting value (y) | Value of LHS (4y) | Value of RHS (20) | Whether LHS and RHS are equal |
| 1 | = 4×1 = 4 |
20 | No |
| 2 | =4×2 = 8 |
20 | No |
| 3 | =4×3 = 12 |
20 | No |
| 4 | =4×4 = 16 |
20 | No |
| 5 | =4×5 = 20 |
20 | Yes |
As LHS=RHS for y = 5,
Hence y = 5 is the solution of the given equation.
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