The correct option is B (2,1)
Given,
2y+x=4⇒x=4−2y …(i)
and 3y−12x=2…(ii)
Step 1: Find the value of y
Substituting x=4−2y in (ii), we get
Equation (ii) → 3y−12(x)=2
3y−12(4−2y)=2
⇒3y−2+y=2⇒4y=2+2⇒4y=4⇒y=1
Step 2: Now, Find the value of x
Substitute y=1 in equation (i)
Equation (i) → x=4−2(y)
x=4−2(1)
⇒x=4−2=2
∴x=2,y=1
∴ Required solution for the given pair of equations is (2,1)