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Question

Find the solution for the following pair of equations
2y+x=4
3yāˆ’12x=2

A
(1,2)
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B
(2,1)
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C
(0,2)
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D
(2,3)
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Solution

The correct option is B (2,1)
Given,
2y+x=4x=42y (i)
and 3y12x=2(ii)

Step 1: Find the value of y
Substituting x=42y in (ii), we get
Equation (ii) 3y12(x)=2
3y12(42y)=2
3y2+y=24y=2+24y=4y=1

Step 2: Now, Find the value of x
Substitute y=1 in equation (i)
Equation (i) x=42(y)
x=42(1)
x=42=2
x=2,y=1

Required solution for the given pair of equations is (2,1)

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