Find the solution for the pair of linear equations:
2x+4y=12
4x+2y=18
(4,1)
Given that,
2x+4y=12
⇒2x=12−4y
⇒x=12−4y2
⇒x=6−2y .................(i)
Now putting this value of x in the second equation,
4x+2y=18,
we get:
4(6−2y)+2y=18
⇒24−8y+2y=18
⇒6y=6
Thus, y=1
Now, putting this value of y in equation (i), we get,
x=6−2(1)
⇒x=4