Question

Find the solution of $\frac{2}{x+3}-\frac{4}{x-3}=\frac{-6}{x+3}$.

• A. $9$
• B. $-1$
• C. $-3$
• D. $3$

Answer 1

The correct option is A $9$

Given, $\frac{2}{x+3}-\frac{4}{x-3}=\frac{-6}{x+3}$

$\Rightarrow$ $\frac{2}{x+3}-\frac{4}{x-3}+\frac{6}{x+3}=0$

Multiply equation by $(x+3)(x-3)$, we get,

$\Rightarrow 2(x-3)-4(x+3)+6(x-3)=0$

$\Rightarrow 8(x-3)-4(x+3)=0$

$\Rightarrow 2(x-3)-(x+3)=0$

$\Rightarrow 2x-6-x-3=0$ ...[By Distribution Law]

$\Rightarrow x-9=0$

$\Rightarrow x=9$.

Hence, option $A$ is correct.