Find the solution of the differential equation.
$d x - d y + y d x + x d y = 0$

Open in App

Solution

Given the differential equation
$d x - d y + y d x + x d y = 0$ can be written as
$d (x - y) + d (x y) = 0$
Now integrating we have
$x - y + x y = c$ [Where $c$ is an integrating constant]

Suggest Corrections

Similar questions

d x - d y + y d x + x d y = 0

y d x - x d y + log x d x = 0

{(\frac{d y}{d x})}^{2} - x (\frac{d y}{d x}) + y = 0

y d x - x d y + 3 x^{2} y^{2} e^{x^{3}} d x = 0

(\frac{d y}{d x}) - x \frac{d y}{d x} + y = 0

Join BYJU'S Learning Program