Find the solution set for -1-2-3- -6-

The correct option is D [ ∞,0]∪ [4,∞]Option (c) is the correct answer. Check the video for the approach. ...

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Solving Inequalities

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Question

Find the solution set for |a-1| + |a-2| + |a-3| $\geq$ 6.

\leq

\leq

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-4

\leq

\leq

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[- \infty, 0] \cup [4, \infty]

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0 < x < 6

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Solution

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Similar questions

Establish the following vector inequalities geometrically or otherwise:

(a) |a + b| ≤ |a| + |b|

(b) |a + b| ≥ ||a| − |b||

(d) |a − b| ≥ ||a| − |b||

When does the equality sign above apply?

a = i - j + k, a \cdot b = 0, a \times b = c,

c = - 2 i - j + k

b

Given a + b + c + d = 0, which of the following statements are correct:

(a) a, b, c, and d must each be a null vector,

(b) The magnitude of (a + c) equals the magnitude of (b + d),

(d) b + c must lie in the plane of a and d if a and d are not collinear, and in the line of a and d, if they are collinear?

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