Find the solution set of the inequality $x^{2} - x - 6 < 0$ .

x > - 2

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- 2 < x < 3

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x > 3

and

x < - 2

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x > 3

x < - 2

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x < 3

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Solution

The correct option is B $- 2 < x < 3$
Given, $x^{2} - x - 6 < 0$
$\Rightarrow x^{2} - 3 x + 2 x - 6 < 0$
$\Rightarrow (x - 3) (x + 2) < 0$
$\Rightarrow - 2 < x < 3$

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