Find the solution to the following system of linear equations:
3x-y+9=0
3x+4y-6=0

(-2, 3)

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(1, 3)

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(2, -3)

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(-2, -3)

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Solution

The correct option is A
(-2, 3)

3x-y+9=0…(I)

3x+4y-6=0..(II)

From the equation I we get,

y=3x+9

Substituting this value of y in equation II we get,

3x+4(3x+9)-6=0

⇒15x+30=0

⇒x=-2

Substituting this value of y in equation I we get,

y=3

Hence the solution is (-2, 3).

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