Question

Find the speed of light in diamond if it's refractive index is 2.5

Answer 1

Answer : The speed of light in Diamond = 1.2×10⁸ m/sec.

Speed of light in vacuum c = 3×10⁸m/sec

Given refractive index of Diamond(n)=2.5

Let the speed of light in Diamond be 'x' m/sec.

We have,

Refractive index n = Speed of light in vacuum/Speed of light in medium

⇒ 2.5 = 3×10⁸/x

⇒ x = 3×10⁸/2.5

⇒ x = 1.2×10⁸ m/sec

Therefore, the speed of light in Diamond=1.2×10⁸m/sec.