Find the square by using the identities.
$(2 x y + 5 y)^{2}$

4 y^{2} y^{2} + 20 y^{2} + 25 x y^{2}

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4 x^{2} y^{2} + 20 x y^{2} + 25 y^{2}

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4 x y^{2} y^{2} + 20 x y^{2} + 25 y x^{2}

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4 x^{2} y^{3} + 20 x y^{2} + 25 y^{2}

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Solution

The correct option is D $4 x^{2} y^{2} + 20 x y^{2} + 25 y^{2}$
$(2 x y + 5 y)^{2}$
Using,
$(a + b)^{2} = a^{2} + 2 a b + b^{2}$ we get,
$= (2 x y)^{2} + 2 (2 x y) (5 y) + (5 y)^{2}$
$= 4 x^{2} y^{2} + 20 x y^{2} + 25 y^{2}$

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