Find the square of: $2 a + b$ .

4 a^{2} - 4 b + b^{3}

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a^{2} + 4 a b + b^{3}

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a^{2} - 4 b + b^{2}

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4 a^{2} + 4 a b + b^{2}

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Solution

The correct option is D $4 a^{2} + 4 a b + b^{2}$
Given, $2 a + b$ .

On squaring, we get, $(2 a + b)^{2}$ .

We know, $(x + y)^{2} = x^{2} + y^{2} + 2 x y$ .

Then,
$(2 a + b)^{2}$
$= (2 a)^{2} + b^{2} + 2 (2 a) (b)$
$= 4 a^{2} + 4 a b + b^{2}$ .

Therefore, option $D$ is correct.

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Similar questions

$4 a^{2} + b^{2} + 4 a b + 8 a + 4 b + 4$ =?

(a) $(2 a + b + 2)^{2}$

(b) $(2 a - b + 2)^{2}$

(d) None of these

(2 a + b)^{2} = 4 a^{2} + b^{2} + 4 a b

4 a^{2} + 4 a b + b^{2} =

State True or False:

On subtracting $a^{2} + a b + b^{2}$ from $4 a^{2} - 3 a b + 2 b^{2}$ , the answer is $3 a^{2} - 4 a b + b^{2}$ .

8 a^{3} - b^{3} - 4 a x + 2 b x

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