Find the square of $53$ .

2890

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1809

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280

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2809

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Solution

The correct option is D $2809$
$53^{2} = 53 \times 53 = (50 + 3) (50 + 3)$
$= 50 (50 + 3) + 3 (50 + 3)$
$= 2500 + 150 + 150 + 9$
$= 2809$

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Question 53

Perimeter of a square and a rectangle is same. If a side of the square is 15 cm and one side of the rectangle is 18 cm, find the area of the rectangle.

Q. In

□

IJKL, side IJ || side KL

∠

I =

108^{°}

∠

K =

53^{°}

then find the measure of

∠

J and

∠

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Find the square of 53.

The correct option is D 2809532=53×53=(50+3)(50+3) =50(50+3)+3(50+3) =2500+150+150+9 =2809

Find the square of $53$ .

The correct option is D $2809$
$53^{2} = 53 \times 53 = (50 + 3) (50 + 3)$
$= 50 (50 + 3) + 3 (50 + 3)$
$= 2500 + 150 + 150 + 9$
$= 2809$