Question

Find the square of the following : $0.1x+0.3y$

Answer 1

Step 1 : First we need to identify the identity we can use, here we need to find the square, so we can use ${(a+b)}^2=a^2+2ab+b^2$

Step 2 : Now if we compare the question with the identity we get $a=0.1x,b=0.3y$

$$\begin{gathered} {(0.1x+0.3y)}^2={(0.1x)}^2+2(0.1x)(0.3y)+{(0.3y)}^2 \\ =0.01x^2+0.06xy+{0.09y}^2 \end{gathered}$$

Hence the square of $0.1x+0.3y$ is $0.01x^2+0.06xy+{0.09y}^2$