Question

Find the square root : $8+2\sqrt{7}$

Answer 1

$\sqrt{8+2\sqrt{7}}$
$=\sqrt{1+7+2\sqrt{7}}$
$=\sqrt{{\left(1\right)}^2+{\left(\sqrt{7}\right)}^2+2\times 1\times \sqrt{7}}$
$=\sqrt{{\left(\sqrt{7}+1\right)}^2}$
$=\sqrt{7}+1$