Question

Find the square root of $28-6\sqrt{3}$.

• A. $\pm (\sqrt{3}-1)$.
• B. $(3\sqrt{3}+1)$.
• C. $\pm (3\sqrt{3}-1)$.
• D. $(3\sqrt{3}-1)$.

Answer 1

Answer: (C)

$\pm (3\sqrt{3}-1)$.

Now,

$28-6\sqrt{3}$

$=28-2.3\sqrt{3}.1$

$=27+1-2.3\sqrt{3}.1$

$=(3\sqrt{3}{)}^2+(1{)}^2-2.3\sqrt{3}.1$

$=(3\sqrt{3}-1{)}^2$

So square root of $=28-6\sqrt{3}$ is $\pm (3\sqrt{3}-1)$.