Question

Find the square root of $390625$ using repeated subtraction.

Answer 1

The procedure to find square root of $390625$ is shown in figure.

In this first a group of two numbers has been done first like

$1^{st}$ group: $39$, $2^{nd}$ group: $06$ and $3^{rd}$ group: $25$.

At first, we need to take a number whose square comes near to or equal to $39$. That would be $36$ square of $6$. It is written as shown.

After subtraction, the remainder is $3$.

Now bring another group down. Here the number becomes $306$.

Again repeat the same process to make the remainder zero.