Find the square root of a number $9604$ by Prime Factorisation Method.

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Solution

By using methof of factorisation:
$9604 = 2 \times 2 \times 7 \times 7 \times 7 \times 7 = 2^{2} \times 7^{2} \times 7^{2}$
Taking square root, we have
$\sqrt{9604} = \sqrt{2^{2} \times 7^{2} \times 7^{2}}$
$= 2 \times 7 \times 7$
$= 98$

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Question 4 (vi)
Find the square roots of the following numbers by the Prime Factorizationmethod:

9604

Find the square root of the following number by prime factorisation method
(i) $729$
(ii) $400$
(iii) $1764$
(iv) $4096$
(v) $7744$
(vi) $9604$
(vii) $5929$
(viii) $9216$
(ix) $529$
(x) $8100$

Q. Find the square root of a number

8100

by Prime Factorisation Method.

Q. Find the square root of a number

7744

by Prime Factorisation Method.

Find the square roots of the following numbers by the Prime Factorisation Method.

(i) $729$ (ii) $400$ (iii) $1764$ (iv) $4096$ (v) $7744$ (vi) $9604$ (vii) $5929$ (viii) $9216$ (ix) $529$ (x) $8100$

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Find the square root of a number 9604 by Prime Factorisation Method.

By using methof of factorisation:9604=2×2×7×7×7×7=22×72×72 Taking square root, we have√9604=√22×72×72=2×7×7 =98

Find the square root of a number $9604$ by Prime Factorisation Method.

By using methof of factorisation:
$9604 = 2 \times 2 \times 7 \times 7 \times 7 \times 7 = 2^{2} \times 7^{2} \times 7^{2}$
Taking square root, we have
$\sqrt{9604} = \sqrt{2^{2} \times 7^{2} \times 7^{2}}$
$= 2 \times 7 \times 7$
$= 98$