Question

Find the square root of each of the following correct to three places of decimal :

(i) 5 (ii) 7
(iii) 17 (iv) 20
(v) 66 (vi) 427
(vii) 1.7 (viii) 23.1
(ix) 2.5 (x) 237.615
(xi) 15.3215 (xii) 0.9
(xiii) 0.1 (xiv) 0.016
(xv) 0.00064 (xvi) 0.019
(xvii) $\frac{7}{8}$ (xviii)$\frac{5}{12}$
(xix) $2\frac{1}{2}$ (xx) $287\frac{5}{8}$

Answer 1

$\left(i\right)\sqrt{5}=\sqrt{5.000000}$

= 2.236

$\left(ii\right)\sqrt{7}=\sqrt{7.00000000}$

=2.6457

=2.646

$\left(iii\right)\sqrt{17}=\sqrt{17.000000}$

=4.123

$\left(iv\right)\sqrt{20}=\sqrt{20.000000}$

=4.472

$\left(v\right)\sqrt{66}=\sqrt{66.000000}$

=8.124

$\left(vi\right)\sqrt{427}=\sqrt{427.000000}$

= 20.664

$\left(vii\right)\sqrt{1.7}=\sqrt{1.70000000}$

=1.3038=1.304

$\left(viii\right)\sqrt{23.1}=\sqrt{23.100000}$

=4.806

$\left(ix\right)\sqrt{2.5}=\sqrt{2.500000}$

=1.581

$\left(x\right)\sqrt{237.615}=\sqrt{237.615000}$

=15.4147=15.415

$\left(xi\right)\sqrt{15.3215}=\sqrt{15.321500}$

= 3.9142 = 3.914

$\left(xii\right)\sqrt{0.9}=\sqrt{0.900000}$

= 0.9486 = 0.949

$\left(xiii\right)\sqrt{0.1}=\sqrt{0.100000}$

= 0.316

$\left(xiv\right)\sqrt{0.016}=\sqrt{0.016000}$

= 0.1264 = 0.126

$\left(xv\right)\sqrt{0.00064}=\sqrt{0.000640}$

= 0.0252 = 0.025

$\left(xvi\right)\sqrt{0.019}=\sqrt{0.019000}$

= 0.1378 = 0.138

$\left(xvii\right)\sqrt{\frac{7}{8}}=\sqrt{0.875}$

= 0.9354 = 0.935

$\left(xviii\right)\sqrt{\frac{5}{12}}=\sqrt{0.416666}$

= 0.6454 = 0.645

$\left(xix\right)\sqrt{2\frac{1}{2}}=\sqrt{\frac{5}{2}}=\sqrt{2.5}$

= 1.581

$\left(xx\right)\sqrt{287\frac{5}{8}}=\sqrt{\frac{2301}{8}}=\sqrt{287.625}$

= 16.959