Find the square root of the following number by the prime factorisation method.
$5929$

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Solution

The factors of $5929$ is,

$5929 = 7 \times 7 \times 11 \times 11$

Take square root both sides,

$\sqrt{5929} = \sqrt{7 \times 7 \times 11 \times 11}$

$= \sqrt{7^{2} \times 11^{2}}$

$= \sqrt{{(7 \times 11)}^{2}}$

$= 7 \times 11$

$= 77$

Therefore, the square root of 5929 is 77.

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Find the square roots of the following numbers by the Prime Factorization method:
5929

Find the square root of the following number by prime factorisation method
(i) $729$
(ii) $400$
(iii) $1764$
(iv) $4096$
(v) $7744$
(vi) $9604$
(vii) $5929$
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(x) $8100$

Find the square roots of the following numbers by the Prime Factorisation Method.

(i) $729$ (ii) $400$ (iii) $1764$ (iv) $4096$ (v) $7744$ (vi) $9604$ (vii) $5929$ (viii) $9216$ (ix) $529$ (x) $8100$

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Find the square root of the following number by the prime factorisation method.5929

The factors of 5929 is, 5929=7×7×11×11 Take square root both sides, √5929=√7×7×11×11 =√72×112 =√(7×11)2 =7×11 =77 Therefore, the square root of 5929 is 77.

Find the square root of the following number by the prime factorisation method.
$5929$

The factors of $5929$ is,

$5929 = 7 \times 7 \times 11 \times 11$

Take square root both sides,

$\sqrt{5929} = \sqrt{7 \times 7 \times 11 \times 11}$

$= \sqrt{7^{2} \times 11^{2}}$

$= \sqrt{{(7 \times 11)}^{2}}$

$= 7 \times 11$

$= 77$

Therefore, the square root of 5929 is 77.