Question

Find the square root of the following numbers by factorisation:
$\left(i\right)196\left(ii\right)256\left(iii\right)10404\left(iv\right)1156\left(v\right)13225$.

Answer 1

$\left(i\right)196=2\times 2\times 7\times 7\therefore squareroot=2\times 7=14\left(ii\right)256=16\times 16\therefore squareroot=16\left(iii\right)10404=9\times 4\times 17\times 17\therefore squareroot=3\times 2\times 17=102\left(iv\right)1156=2\times 2\times 17\times 17\therefore squareroot=2\times 17=34\left(v\right)13225=5\times 5\times 23\times 23\therefore squareroot=5\times 23=115$