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A |x2−2x+3|We find the square root of the given polynomial x4−4x3+10x2−12x+9 by following the steps shown below:
Step 1. Compute the square root of the leading term (x4) and put it, (x2), in the two places shown.
Step 2. Subtract and bring down the next two terms.
Step 3. Double the currently displayed quotient (x2) to 2x2. Then add a new term, x, to the quotient such that the result will remove the first term, (−4x3), in the current partial remainder.
Step 4. Repeat steps 2 and 3 until done.
The division is as follows:
Hence, the square root of x4−4x3+10x2−12x+9 is x2−2x+3.