Question

Find the strength of 500 mL of a 1 M glucose solution.

• A. 90 g/L
• B. 45 g/L
• C. 180 g/L
• D. 135 g/L

Answer 1

The correct option is C 180 g/L

Molarity = $\frac{\text{number of moles}}{\text{total volume (mL)}}\times 1000$
$\Rightarrow 1=\frac{\text{number of moles}}{500}\times 1000$
Number of moles = 0.5
Mass of glucose = 0.5 mol $\times$ 180 g/mol = 90 g

$\text{Strength}=\frac{\text{mass of solute}}{\text{volume of solution (L)}}=\frac{90}{0.5}=180g/L$
So, the strength of glucose will be = 180 g/L