Find the sub-duplicate ratio of 81 : 64 ?

8 : 9

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4 : 9

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9 : 8

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7 : 8

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Solution

The correct option is C 9 : 8
sub-duplicate ratio of $a^{2} : b^{2} = a : b$
here $81 : 64$ = $\frac{81}{64} = (\frac{9}{8})^{2}$
there fore duplicate ratio of $81 : 64 = 9 : 8$

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\frac{1}{25} : \frac{1}{64}

Find the compounded ratio of the duplicate ratio of 3 : 5, the reciprocal ratio of 4 : 25, and the sub-duplicate ratio of 16 : 81.

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