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Question

Find the sum
1+3+5+7+......+199.

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Solution

Sum of 1+3+5+7+.....+199

a=1 d=2

Finding nth term in A.P; an=a+(n1)d

If an=199 then 199=1+(n1)2

n=100

Therefore, no. of terms =n=100

sum of 100 terms = n2[a+an]=1002[1+199]

=1002[200]

=10000

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