Question

Find the sum $2\frac{4}{5}+1\frac{3}{10}+3\frac{1}{15}$.

Answer 1

We have:
$$\begin{gathered} 2\frac{4}{5}+1\frac{3}{10}+3\frac{1}{15} \\ =\frac{14}{5}+\frac{13}{10}+\frac{46}{15} \\ 5\underline{\overline{)5,10,15}} \\ \underline{2\underline{\overline{)1,2}},3} \\ 3\overline{)\underline{1,1,3}} \\ \underline{\underline{\overline{)1,1}},1} \\ \mathrm{L}.\mathrm{C}.\mathrm{M}.\mathrm{of}5,10\mathrm{and}15=\left(5\times 2\times 3\right)=30 \\ =\frac{84+39+92}{30}\left\{\left[30÷5=6,6\times 14=84\right],\left[30÷10=3,3\times 13=39\right]\mathrm{and}\left[30÷15=2,2\times 46=92\right]\right\} \\ =\frac{{\cancel{215}}^{43}}{{\cancel{30}}_6} \\ =\frac{43}{6} \\ =7\frac{1}{6} \end{gathered}$$