Find the sum :
$25 + 28 + 31 + . . . . + 100.$

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Solution

Here,
$a = 25, d = 3, l = 100$

Let the total terms be $n$ .

$T_{n} = 100$

$a + (n - 1) d = 100$

$3 n + 22 = 100$

$n = 26$

Required sum = $\frac{n}{2} (a + l)$

$= 13 (25 + 100) = 1625$

Hence, the required sum is 1625.

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