Question

Find the sum:
$3\frac{2}{3}+1\frac{5}{6}+2$

Answer 1

We have:



$$\begin{gathered} 3\frac{2}{3}+1\frac{5}{6}+2 \\ =\frac{11}{3}+\frac{11}{6}+\frac{2}{1}\mathrm{L}.\mathrm{C}.\mathrm{M}.\mathrm{of}3\mathrm{and}6=(2\times 3)=6 \\ =\frac{\left(22+11+12\right)}{6}\left\{\left[6÷3=2,2\times 11=22\right],\left[6÷6=1,1\times 11=11\right]\mathrm{and}\left[6÷1=6,6\times 2=12\right]\right\} \\ =\frac{{\cancel{45}}^{15}}{{\cancel{6}}_2}=\frac{15}{2}=7\frac{1}{2} \end{gathered}$$
234+556