Question

Find the sum:
$\frac{7}{12}+\frac{9}{16}$

Answer 1

L.C.M. of 12 and 16 = (2 $\times$ 2 $\times$ 2 $\times$ 2 $\times$ 3) = 48


Now, we have:

$$\begin{gathered} \frac{7}{12}=\frac{7\times 4}{12\times 4}=\frac{28}{48};\frac{9}{16}=\frac{9\times 3}{16\times 3}=\frac{27}{48} \\ \therefore \frac{7}{12}+\frac{9}{16}=\frac{28}{48}+\frac{27}{48}=\frac{\left(28+27\right)}{48}=\frac{55}{48}=1\frac{7}{48} \end{gathered}$$