Find the sum
$82$ kg $250$ g, $22$ kg $400$ g and $8$ kg $815$ g

Open in App

Solution

Given
kg g
$82$ $250$
$22$ $400$
+ $8$ $815$

$112 1465$
_
We know that
$1000$ g $= 1$ kg
$1465$ g $= 1$ kg $465$ g
Hence, the final answer is $113$ kg $465$ g

Suggest Corrections

Similar questions

Question 108.
Alik purchased 1 kg 200 g potatoes, 250 g dhania, 5 kg 300g onion, 500 g palak and 2 kg 600 g tomatoes. Find the total weight of his purchases in kilograms.

Q. Question 8
Shyam bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?

Shyama bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?

Q. A grocer purchased 200 kg of rice at Rs 25 per kg. He sold 80 kg of it at a gain of 10% and 40 kg at a loss of 4%. At what rate per kg should he sell the remainder to gain 8% on his total investment?

Find the sum of $5836 k g 250 g$ and $2954 k g 825 g$

Join BYJU'S Learning Program

Find the sum82kg 250g, 22kg 400g and 8kg 815g

Given kg g 82 250 22 400+8 815__________1121465___________We know that 1000g =1 kg1465g =1 kg 465gHence, the final answer is 113kg 465g

Find the sum
$82$ kg $250$ g, $22$ kg $400$ g and $8$ kg $815$ g

Given
kg g
$82$ $250$
$22$ $400$
+ $8$ $815$

$112 1465$
_
We know that
$1000$ g $= 1$ kg
$1465$ g $= 1$ kg $465$ g
Hence, the final answer is $113$ kg $465$ g