Question

Find the sum and product of roots of the quadratic equation $\left[x^2-4\sqrt{3}x+9=0\right]$

Answer 1

$x^2-4\sqrt{3}+9=0$

Here $a=1,b=-4\sqrt{3},c=9$

Now,

Sum of roots $=\frac{-b}{a}=\frac{-(-4\sqrt{3})}{1}=4\sqrt{3}$

Product of roots $=\frac{c}{a}=\frac{9}{1}=9$

Hence the sum and product of roots of the given equation is $4\sqrt{3}$ and $9$ respectively.