Find the sum and product of the zeroes of the following quadratic polynomials.
$5 x^{2} - 8 x + 3$

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Solution

The standard form of any polynomial is $(coefficient of x^{2}) x^{2} + (coefficient of x) x + constant term$ .
Here, coefficient of $x^{2}$ is $5$ , coefficient of $x$ is $- 8$ , and constant term is $3$ .
Step 1: To find the sum of zeroes.
Sum of zeroes = $\frac{- (coefficient of x)}{coefficient of x^{2}} = \frac{- (- 8)}{5} = \frac{8}{5}$
Step 2: To find the product of zeroes.
Product of zeroes = $\frac{constant term}{coefficient of x^{2}} = \frac{3}{5}$
Hence, the sum and product of zeroes are $\frac{8}{5}$ and $\frac{3}{5}$ respectively.

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