Question

Find the sum:
$\frac{4}{9}+\frac{8}{9}$

Answer 1

Given
$\frac{4}{9}+\frac{8}{9}$
$=\frac{4+8}{9}$ (on taking $9$ as L.C.M of the denominator)
$=\frac{12}{9}$
$=\frac{4}{3}$ (on dividing both numerator and denominator by $3$)
$\therefore \frac{4}{9}+\frac{8}{9}=\frac{4}{3}$
$=1\frac{1}{3}$