Question

Find the sum $:$

$\frac{2}{9}+\frac{1}{3}+\frac{4}{15}$

Answer 1

Step 1: Find the least common multiple ( L.C.M) of denominators of the given fraction:

Given fractions: $\frac{2}{9},\frac{1}{3}\text{and}\frac{4}{15}$

L.C.M of $\left(9,3,15\right)$ $=45$

Step 2: Make the equivalent fraction with denominator $45$ and add them:

$\frac{2}{9}+\frac{1}{3}+\frac{4}{15}$

$\Rightarrow \frac{2\times 5+1\times 15+4\times 3}{45}$

$\Rightarrow \frac{10+15+12}{45}$ $=\frac{37}{45}$

Therefore, the sum of $\frac{2}{9}+\frac{1}{3}+\frac{4}{15}$ is $\frac{37}{45}$