Question

Find the sum $:$

$\frac{4}{7}+\frac{1}{14}+\frac{11}{21}$

Answer 1

Step 1: Find the least common multiple ( L.C.M) of denominators of given fraction

Factors of $7=7\times 1$

Factors of $14=7\times 2\times 1$

Factors of $21=7\times 3\times 1$

In take highest power of the number

L.C.M of $\left(7,14,21\right)$ $=7^1\times 2^1\times 3^1=42$

Step 2: Make the equivalent fraction with denominator $42$ and add them

$\Rightarrow \frac{4\times 6+1\times 3+11\times 2}{42}$

$=\frac{24+3+22}{42}$ $=\frac{49}{42}$$=$ $1\frac{7}{42}$

Therefore, the sum of $\frac{4}{7}+\frac{1}{14}+\frac{11}{21}$ is $1\frac{7}{42}$ or $1\frac{1}{6}$.