Find the sum:
(i) $7 x - 4 y, 2 x + 6 y$
(ii) $9 x^{2} + 5 x, 6 x^{2} - 2 x$
(iii) $2 a + b, 6 a^{2} - 7 a - b$

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Solution

(i) $(7 x - 4 y) + (2 x + 6 y) = 7 x + 2 x - 4 y + 6 y = 9 x + 2 y$

(ii) $(9 x^{2} + 5 x) + (6 x^{2} - 2 x) = 9 x^{2} + 6 x^{2} + 5 x - 2 x = 15 x^{2} + 3 x$

(iii) $(2 a + b) + (6 a^{2} - 7 a - b) = 6 a^{2} + 2 a - 7 a + b - b = 6 a^{2} - 5 a$

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B = 5 x + 4 y

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If $\frac{3 x - 4 y}{2 x - 3 y} = \frac{5 x - 6 y}{4 x - 5 y}$ , find x : y.

a

b

p (x) = (x^{2} + 5 x + 6) (x^{2} + 2 x - a)

q (x) = (x^{2} - x - 2) (x^{2} + 7 x + b)

(x + 2) (x - 2)

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