Find the sum:
$(- 10) + (- 10) + (- 10) + . . . . . . . 10 times$

$- 100$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$100$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$0$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$1000$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$- 100$

If the given numbers are of like signs, then add the absolute values directly and give the common sign for the result.
$(- 10) + (- 10) + (- 10) + . . . . . . . 10 times$
Here, the common sign is $" - "$
So, $\begin{array}{rcl} (- 10) + (- 10) + (- 10) + . . . . . . . 10 times \\ = & - (10 \times 10) \\ = & - 100 \end{array}$
Hence, option (A) is correct.

Suggest Corrections

Similar questions

Find the sum : $\sum_{n = 1}^{10} {{(\frac{1}{2})}^{n - 1} + {(\frac{1}{5})}^{n + 1}}$

\sum_{r = 1}^{10} (r^{2} + 1) (r!)

Find the sum : $- 10 + (- 10) + (- 10) + . . . . . . . 10 t i m e s$

S

S = \sum_{n = 1}^{10} (2 n + \frac{1}{2})

\sum 0 \leq i \sum j \leq 10 (^{10} C_{j}) (^{j} C_{i})

Join BYJU'S Learning Program