Find the sum of 1+2+3+4+5+6………..+14+15
Finding the sum:
We know that, Sum of the first n natural number=n(n+1)2
We have given 1+2+3+4+5+6………..+14+15
Where, n=15 (Total number of terms)
Sum of natural number=n(n+1)2
=15(15+1)2
=15(16)2
Therefore, the sum of natural numbers from 1 to 15 is 120.
The value of -C115+2·C215-3·C315+…-15·C1515+C114+C314+C514+…+C1114 is
The sum of the series 1+(1+2)+(1+2+3)+(1+2+3+4)+……..+(1+2+3+4+…+20) is
Sum of infinite terms A,AR,AR2,AR3,… is 15. If the sum of the squares of these terms is 150, then find the sum of AR2,AR4,AR6,….