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Question

Find the sum of 10 terms if the nth term of a sequence is 3n- 2.


A

( - 1) - 20

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B

( - 1) - 20

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C

( - 1) - 20

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D

( - 1) - 30

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Solution

The correct option is C

( - 1) - 20


Sn = ∑tn

S10 =10n=1(3n - 2)

= 10n=13n - 10n=12

= 3(3101)2 - 2×10

= 32 (310 - 1) - 20


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