Find the sum of 12 terms of -6, 0, 6, 12...

300

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332

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324

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294

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330

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Solution

The correct option is C 324
Soln:

$S_{n} = \frac{n (a + l)}{2}$

In the question, a = -6

l = a + (n -1)d = -6 + (12 – 1)(6) = 60

So, $S_{12} = \frac{12 (- 6 + 60)}{2}$ = 324

Hence option (c)

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Find the sum of the first
(i) 11 terms of the A.P.: 2,6,10,14,...
(ii) 13 terms of the A.P.: -6,0,6,12,...
(iii) 51 terms of the A.P.: whose second term is 2 and fourth term is 8.

Q. Find the sum of the first

(i) 11 terms of the A.P.2, 6, 10. 14

(ii) 13 terms of the A.P. −6, 0, 6, 12, ...

(iii) 51 terms of the A.P. : whose second term is 2 and fourth term is 8.

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Find the sum of 12 terms of -6, 0, 6, 12...

The correct option is C 324Soln: Sn=n(a+l)2 In the question, a = -6 l = a + (n -1)d = -6 + (12 – 1)(6) = 60 So, S12=12(−6+60)2= 324 Hence option (c)

The correct option is C 324
Soln:

$S_{n} = \frac{n (a + l)}{2}$

In the question, a = -6

l = a + (n -1)d = -6 + (12 – 1)(6) = 60

So, $S_{12} = \frac{12 (- 6 + 60)}{2}$ = 324

Hence option (c)