Find the sum of –312, 39 and 192.

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Solution

According to the question,

To find the sum of the given three integers (–312) + 39 + 192.
First add 39 and 192, i.e., 39 + 192 = 231
then, add (-312) and 231, i.e., –312 + 231 = –81
Hence, the sum of the three integers will be -81.

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