Question

Find the sum of additive inverse and multiplicative inverse of $-3$. [2 marks]

Answer 1

Given number: $-3$

Additive inverse of $-3=3$
[0.5 mark]

Multiplicative inverse of $-3=-\frac{1}{3}$
[0.5 mark]


$\therefore$ Sum $=\left(3\right)+(-\frac{1}{3})$

$=\frac{(3\times 3)-1}{3}$

$=\frac{9-1}{3}$

$=\frac{8}{3}$
[1 mark]

Hence, the sum of additive inverse and multiplicative inverse of $-3$ is $\frac{8}{3}$.